dmi: prevent linked list corruption

Adding the same item to a given linked list more than once is guaranteed
to break and corrupt the list.  This is however what we do in dmi_scan
since commit 79da472111 ("x86: fix DMI out
of memory problems").

Given that there is absolutely no interest in saving empty OEM strings
anyway, I propose the simple and efficient fix below: we discard the empty
OEM strings altogether.

Signed-off-by: Jean Delvare <[email protected]>
Acked-by: Parag Warudkar <[email protected]>
Cc: Ingo Molnar <[email protected]>
Cc: Thomas Gleixner <[email protected]>
Cc: Matt Domsch <[email protected]>
Signed-off-by: Andrew Morton <[email protected]>
Signed-off-by: Linus Torvalds <[email protected]>
This commit is contained in:
Jean Delvare 2008-02-23 15:23:55 -08:00 • committed by Linus Torvalds
commit 43fe105a5c

View file

@ -217,10 +217,6 @@ static void __init dmi_save_devices(const struct dmi_header *dm)
}
}
static struct dmi_device empty_oem_string_dev = {
.name = dmi_empty_string,
};
static void __init dmi_save_oem_strings_devices(const struct dmi_header *dm)
{
int i, count = *(u8 *)(dm + 1);
@ -229,10 +225,8 @@ static void __init dmi_save_oem_strings_devices(const struct dmi_header *dm)
for (i = 1; i <= count; i++) {
char *devname = dmi_string(dm, i);
if (!strcmp(devname, dmi_empty_string)) {
list_add(&empty_oem_string_dev.list, &dmi_devices);
if (devname == dmi_empty_string)
continue;
}
dev = dmi_alloc(sizeof(*dev));
if (!dev) {