freezer: unexport refrigerator() and update try_to_freeze() slightly

There is no reason to export two functions for entering the
refrigerator.  Calling refrigerator() instead of try_to_freeze()
doesn't save anything noticeable or removes any race condition.

* Rename refrigerator() to __refrigerator() and make it return bool
  indicating whether it scheduled out for freezing.

* Update try_to_freeze() to return bool and relay the return value of
  __refrigerator() if freezing().

* Convert all refrigerator() users to try_to_freeze().

* Update documentation accordingly.

* While at it, add might_sleep() to try_to_freeze().

Signed-off-by: Tejun Heo <[email protected]>
Cc: Samuel Ortiz <[email protected]>
Cc: Chris Mason <[email protected]>
Cc: "Theodore Ts'o" <[email protected]>
Cc: Steven Whitehouse <[email protected]>
Cc: Andrew Morton <[email protected]>
Cc: Jan Kara <[email protected]>
Cc: KONISHI Ryusuke <[email protected]>
Cc: Christoph Hellwig <[email protected]>
This commit is contained in:
Tejun Heo 2011-11-21 12:32:22 -08:00
commit a0acae0e88
15 changed files with 37 additions and 39 deletions

View file

@ -2349,7 +2349,7 @@ int jfsIOWait(void *arg)
if (freezing(current)) {
spin_unlock_irq(&log_redrive_lock);
refrigerator();
try_to_freeze();
} else {
set_current_state(TASK_INTERRUPTIBLE);
spin_unlock_irq(&log_redrive_lock);

View file

@ -2800,7 +2800,7 @@ int jfs_lazycommit(void *arg)
if (freezing(current)) {
LAZY_UNLOCK(flags);
refrigerator();
try_to_freeze();
} else {
DECLARE_WAITQUEUE(wq, current);
@ -2994,7 +2994,7 @@ int jfs_sync(void *arg)
if (freezing(current)) {
TXN_UNLOCK();
refrigerator();
try_to_freeze();
} else {
set_current_state(TASK_INTERRUPTIBLE);
TXN_UNLOCK();