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freezer: unexport refrigerator() and update try_to_freeze() slightly
There is no reason to export two functions for entering the refrigerator. Calling refrigerator() instead of try_to_freeze() doesn't save anything noticeable or removes any race condition. * Rename refrigerator() to __refrigerator() and make it return bool indicating whether it scheduled out for freezing. * Update try_to_freeze() to return bool and relay the return value of __refrigerator() if freezing(). * Convert all refrigerator() users to try_to_freeze(). * Update documentation accordingly. * While at it, add might_sleep() to try_to_freeze(). Signed-off-by: Tejun Heo <[email protected]> Cc: Samuel Ortiz <[email protected]> Cc: Chris Mason <[email protected]> Cc: "Theodore Ts'o" <[email protected]> Cc: Steven Whitehouse <[email protected]> Cc: Andrew Morton <[email protected]> Cc: Jan Kara <[email protected]> Cc: KONISHI Ryusuke <[email protected]> Cc: Christoph Hellwig <[email protected]>
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15 changed files with 37 additions and 39 deletions
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@ -2349,7 +2349,7 @@ int jfsIOWait(void *arg)
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if (freezing(current)) {
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spin_unlock_irq(&log_redrive_lock);
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refrigerator();
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try_to_freeze();
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} else {
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set_current_state(TASK_INTERRUPTIBLE);
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spin_unlock_irq(&log_redrive_lock);
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@ -2800,7 +2800,7 @@ int jfs_lazycommit(void *arg)
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if (freezing(current)) {
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LAZY_UNLOCK(flags);
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refrigerator();
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try_to_freeze();
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} else {
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DECLARE_WAITQUEUE(wq, current);
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@ -2994,7 +2994,7 @@ int jfs_sync(void *arg)
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if (freezing(current)) {
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TXN_UNLOCK();
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refrigerator();
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try_to_freeze();
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} else {
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set_current_state(TASK_INTERRUPTIBLE);
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TXN_UNLOCK();
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